Implementation

dicts = {'a':1, 'b':2, 'c':3}

sport_team = dict([
		('Liverpool', 'Liverpool'),
		('Chelsea', 'London'),
		('Manchester United', 'Manchester')
		('Manchester City', 'Manchester')
		('Arsenal', 'London')
])
print(sport_team)

# Output
{'Liverpool': 'Liverpool', 'Chelsea': 'London', 'Manchester United': 'Manchester', 'Manchester City': 'Manchester', 'Arsenal': 'London'}

sport_team = dict(
		Liverpool= 'Liverpool',
		Chelsea= 'London',
		Manchester United= 'Manchester',
		Manchester City= 'Manchester',
		Arsenal= 'London'
)
print(sport_team)

{'Liverpool': 'Liverpool', 'Chelsea': 'London', 'ManchesterUnited': 'Manchester', 'ManchesterCity': 'Manchester', 'Arsenal': 'London'}

Accessing Dictionary

sport_team[1]

[] Accessing by square bracket

print(sport_team['Liverpool'])
print(sport_team['Arsenal'])

Liverpool
London

If we refer to key that has no dictionary, Python will show Exception

print(sport_team['Chelsea'])